Instructor Solution Manual - College Physics: Reasoning and Relationships (2nd Edition)
Nicholas Giordano
Language: English
Pages: 938
ISBN: 2:00094988
Format: PDF / Kindle (mobi) / ePub
Note: High-quality native PDF. Information refers to the textbook that accompanies this solution manual.
Master the fundamental concepts of physics with COLLEGE PHYSICS: REASONING AND RELATIONSHIPS. The theme of Reasoning and Relationships is reinforced throughout the book, helping you master these concepts, apply them to solve a variety of problems, and appreciate the relevance of physics to your career and your everyday life. By understanding the reasoning behind problem solving, you learn to recognize the concepts involved, think critically about them, and move beyond merely memorizing facts and equations.
Nuclear Reactors, Nuclear Fusion and Fusion Engineering
Optimal Control with Aerospace Applications (Space Technology Library, Volume 32)
Black Holes and Baby Universes and Other Essays
The Theory of Everything: The Origin and Fate of the Universe
time. You can easily check your answers. The total distance for the three parts of the trip is (1.5 m/s) (340 s) + 0 + (0.6 m/s)(1150 s) = 1200 m. The average velocity for the trip is (1200 m)/(340 s + 10 s + 1150 s) = (1200 m)/(1500 s) = 0.80 m/s. * [SSM] P2.38 Recognize the principle. As the ball rolls up the incline it will slow down at a constant rate until it momentarily comes to rest. The ball will then begin rolling back down the incline speeding up at a constant rate. Sketch the problem.
forces acting on the ice skater in the x direction. Her acceleration must then be zero and she will continue traveling at the constant speed of v0 = 8.0 m/s. Knowing the time t = 17 s to travel the length of the pond and since the acceleration is constant (zero), we can use Equation 3.3 to determine the length of the pond: 1 at2 x = x0 + v0t + __ 2 Solve. Inserting a = 0, the starting position of x0 = 0 m, x = 0 + v 0t + 0 x = v0t Inserting the values for v0 and t gives us: x = (8.0 m/s)(17 s) x
distribution allowed without express authorization. ( We can find the stopping distance for a given initial velocity using Equation 3.4. v2 = v02 + 2a∆x Solve. We will do the development for kinetic friction, but the static case is the same. The acceleration for a given coefficient of friction is found by combining our definition of friction with our Newton’s second law equation: −KN −Kmg −Ffriction ______ = m = _______ = −Kg a = _______ m m We can then solve Equation 3.4 for the stopping
71009_ch03.indd 154 8/3/11 7:33 PM © Cengage Learning. All rights reserved. No distribution allowed without express authorization. 4 Forces and Motion in Two and Three Dimensions CONCEPT CHECK 4.1 | Pulling on the Sled The correct answer is (b). If the angle θ is increased beyond 36°, the component of the tension force along the vertical will be larger than mg. The sled will accelerate along y and thus be lifted off the ground. It is then no longer in static equilibrium. 4.2 | Falling
three cables meet. Sketch the problem. Draw a free body diagram from a side view perspective centered on the point where all three cables meet as in Figure Ans4.7. Also draw a free body diagram for the crate. y T3 60Њ x T2 FG Figure Ans 4.7 Identify the relationships. Since this is a case of static equilibrium, ∑Fx = 0 ∑Fy = 0 Solve. Describe all forces in component form: For T3, T3x = T3(cos60°) = 0.5 T3 T3y = (sin60°) T3 = 0.866 T3 The force T1 will be in the negative x direction and the
